Integration by substitution - e^x
Integration by substitution - e^x
Last updated at July 28, 2026 by Teachoo
Transcript
Ex 7.2, 16 Integrate the function: šļ·®2š„ + 3ļ·Æ Step 1: Let 2š„ + 3 = š” Differentiating both sides š¤.š.š”.š„ 2+0= šš”ļ·®šš„ļ·Æ 2= šš”ļ·®šš„ļ·Æ šš„ = šš”ļ·®2ļ·Æ Step 2: Integrating the function ﷮﷮ šļ·®2š„ + 3ļ·Æ ļ·Æ . šš„ Putting 2š„+3=š” & šš„= šš”ļ·®2ļ·Æ = ﷮﷮ šļ·®š”ļ·Æļ·Æ . šš”ļ·®2ļ·Æ = 1ļ·®2ļ·Æ ﷮﷮ šļ·®š”ļ·Æļ·Æ . šš” = 1ļ·®2ļ·Æ šļ·®š”ļ·Æ+š¶ = šļ·®šš + šļ·Æļ·®šļ·Æ + šŖ